# Difference: ForumMSC0001 (1 vs. 5)

#### Revision 52010-01-26 - DickFurnas

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 META TOPICPARENT name="ForumMSC"

Discussion Forum » MSC »

# Integral of X^4/((X-1) * (X-2))

Line: 13 to 13 Changed:
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<
Then, we can do partial fraction decomposition on to find an equivalent expression of the form Clearing denominators gives us the equation 15x-14=A(x-2)+B(x-1), which we can rearrange as 15x-14=(A+B)x-(2A+B). Then, equate the x coefficients on both sides, and the constant expressions on both sides to get the system of equations A+B=15, 14=2A+B. We can solve these to get A=-1, B=16. So,
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Then, we can do partial fraction decomposition on to find an equivalent expression of the form Clearing denominators gives us the equation
15x-14=A(x-2)+B(x-1), which we can rearrange as
=(A+B)x-(2A+B).
Then, equate the x coefficients on both sides, and the constant expressions on both sides to get the system of equations A+B=15,
2A+B=14.
We can solve these to get A=-1, B=16. So, Changed:
<
<
Combining all this, we get >
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Combining all this, we get .
Which can be integrated term-by-term.
-- MattGuay - 2009-10-07
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...and for the details of the partial fractions decomposition: in the initial box with the short answer, each of these links invites you to Show steps which reveals possible steps to arrive at the solution. The entire partial fractions decomposition in the first link is implicit in the long division of its first step.

-- DickFurnas - 2010-01-26

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 META FORM FORM FIELD Title name="DiscussionTopicForm" Title Integral of X^4/((X-1) * (X-2)) Forum ForumMSC
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#### Revision 42009-11-06 - MattGuay

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 META TOPICPARENT name="ForumMSC"

Discussion Forum » MSC »

# Integral of X^4/((X-1) * (X-2))

#### Revision 32009-10-07 - MattGuay

Line: 1 to 1

 META TOPICPARENT name="ForumMSC"

Discussion Forum » MSC »

# Integral of X^4/((X-1) * (X-2))

Line: 11 to 11
(x-1)*(x-2) = x^2-3x+2. So, we can do polynomial long division to get:
Changed:
<
< >
> Then, we can do partial fraction decomposition on to find an equivalent expression of the form Clearing denominators gives us the equation 15x-14=A(x-2)+B(x-1), which we can rearrange as

#### Revision 22009-10-07 - MattGuay

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 META TOPICPARENT name="ForumMSC"

Discussion Forum » MSC »

# Integral of X^4/((X-1) * (X-2))

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I'm doing this for homework and I can't figure out how to simplify X^4/((X-1) * (X-2)). Please help.

-- Main.jts228 - 2009-10-07

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(x-1)*(x-2) = x^2-3x+2. So, we can do polynomial long division to get: Then, we can do partial fraction decomposition on to find an equivalent expression of the form Clearing denominators gives us the equation 15x-14=A(x-2)+B(x-1), which we can rearrange as 15x-14=(A+B)x-(2A+B). Then, equate the x coefficients on both sides, and the constant expressions on both sides to get the system of equations A+B=15, 14=2A+B. We can solve these to get A=-1, B=16. So, Combining all this, we get -- MattGuay - 2009-10-07

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#### Revision 12009-10-07 - jts228

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 META TOPICPARENT name="ForumMSC"

Discussion Forum » MSC »

# Integral of X^4/((X-1) * (X-2))

I'm doing this for homework and I can't figure out how to simplify X^4/((X-1) * (X-2)). Please help.

-- Main.jts228 - 2009-10-07

`<--/commentPlugin-->`

 META FORM FORM FIELD Title name="DiscussionTopicForm" Title Integral of X^4/((X-1) * (X-2)) Forum ForumMSC

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