Line: 1 to 1  

Discussion Forum » MSC » limit  
Line: 17 to 17  
Multiplying by the conjugate may not work here, since we have a power less than 1/2. If you have learned l'Hopital's rule, this provides a way to solve this rather easily, and it seems to me that this is the only way to do it, at least the only straightforward way. However, if you are certain that this problem can be solved without that, we can continue trying some other methods.
 MattGuay  20100226  
Added:  
> > 
Consider a new variable w with x = w^5  DickFurnas  20100226  

Line: 1 to 1  

Discussion Forum » MSC » limit  
Line: 10 to 10  
I understand you must multiply by the conjugate, however I do not know what to do with the result of that multiplication. I cannot get anything to cancel, I am still left with a factor of (x32) in the denominator, which makes the denominator zero.
 Main.bwd28  20100225  
Added:  
> > 
Hello, Multiplying by the conjugate may not work here, since we have a power less than 1/2. If you have learned l'Hopital's rule, this provides a way to solve this rather easily, and it seems to me that this is the only way to do it, at least the only straightforward way. However, if you are certain that this problem can be solved without that, we can continue trying some other methods.  MattGuay  20100226  

Line: 1 to 1  

Added:  
> > 
Discussion Forum » MSC » limit
find the limit: lim x approaches 32 ((x^(1/5)  2)/(x32)) Note: this is not a HW problem, it is not in the textbook. I understand you must multiply by the conjugate, however I do not know what to do with the result of that multiplication. I cannot get anything to cancel, I am still left with a factor of (x32) in the denominator, which makes the denominator zero.  Main.bwd28  20100225
